Question

Имея начальную скорость 36км/ч, троллейбус за 10с прошел путь: а)120м б)100м в)80мс каким ускорением двигался троллейбус в каждом случае и какие скорости он приобретал в конце пути

Answer 1

Кажется так. Но могут быть ошибки в Вычислениях ....

Answer 2

Problem Analysis

We are given the initial velocity of a trolleybus (36 km/h) and the time it takes to travel a certain distance (10 seconds). We need to determine the acceleration of the trolleybus in each case and the final velocity it acquires at the end of the distance.

Solution

To find the acceleration, we can use the formula:

Acceleration (a) = Change in velocity (Δv) / Time (t)

Since the initial velocity is given in km/h, we need to convert it to m/s before calculating the acceleration.

To find the final velocity, we can use the formula:

Final velocity (v) = Initial velocity (u) + (Acceleration (a) * Time (t))

Let's calculate the acceleration and final velocity for each case.

Case a) Distance: 120 m

Given: - Initial velocity (u) = 36 km/h - Time (t) = 10 s - Distance = 120 m

First, let's convert the initial velocity from km/h to m/s: Initial velocity (u) = 36 km/h = (36 * 1000) / 3600 m/s = 10 m/s

Now, let's calculate the acceleration: Acceleration (a) = Change in velocity (Δv) / Time (t) = (Final velocity - Initial velocity) / Time (t)

Since the final velocity is not given, we cannot directly calculate the acceleration. However, we can calculate the final velocity using the formula mentioned above.

Final velocity (v) = Initial velocity (u) + (Acceleration (a) * Time (t))

Substituting the given values: 120 = 10 + (a * 10)

Simplifying the equation: 120 - 10 = 10a 110 = 10a a = 110 / 10 = 11 m/s^2

Now that we have the acceleration, we can calculate the final velocity: Final velocity (v) = Initial velocity (u) + (Acceleration (a) * Time (t)) = 10 + (11 * 10) = 10 + 110 = 120 m/s

Therefore, in case a), the trolleybus had an acceleration of 11 m/s^2 and acquired a final velocity of 120 m/s.

Case b) Distance: 100 m

Given: - Initial velocity (u) = 36 km/h - Time (t) = 10 s - Distance = 100 m

Using the same approach as in case a), let's calculate the acceleration and final velocity.

First, let's convert the initial velocity from km/h to m/s: Initial velocity (u) = 36 km/h = (36 * 1000) / 3600 m/s = 10 m/s

Now, let's calculate the acceleration: Acceleration (a) = Change in velocity (Δv) / Time (t) = (Final velocity - Initial velocity) / Time (t)

Since the final velocity is not given, we cannot directly calculate the acceleration. However, we can calculate the final velocity using the formula mentioned above.

Final velocity (v) = Initial velocity (u) + (Acceleration (a) * Time (t))

Substituting the given values: 100 = 10 + (a * 10)

Simplifying the equation: 100 - 10 = 10a 90 = 10a a = 90 / 10 = 9 m/s^2

Now that we have the acceleration, we can calculate the final velocity: Final velocity (v) = Initial velocity (u) + (Acceleration (a) * Time (t)) = 10 + (9 * 10) = 10 + 90 = 100 m/s

Therefore, in case b), the trolleybus had an acceleration of 9 m/s^2 and acquired a final velocity of 100 m/s.

Case c) Distance: 80 m

Given: - Initial velocity (u) = 36 km/h - Time (t) = 10 s - Distance = 80 m

Using the same approach as in case a) and b), let's calculate the acceleration and final velocity.

First, let's convert the initial velocity from km/h to m/s: Initial velocity (u) = 36 km/h = (36 * 1000) / 3600 m/s = 10 m/s

Now, let's calculate the acceleration: Acceleration (a) = Change in velocity (Δv) / Time (t) = (Final velocity - Initial velocity) / Time (t)

Since the final velocity is not given, we cannot directly calculate the acceleration. However, we can calculate the final velocity using the formula mentioned above.

Final velocity (v) = Initial velocity (u) + (Acceleration (a) * Time (t))

Substituting the given values: 80 = 10 + (a * 10)

Simplifying the equation: 80 - 10 = 10a 70 = 10a a = 70 / 10 = 7 m/s^2

Now that we have the acceleration, we can calculate the final velocity: Final velocity (v) = Initial velocity (u) + (Acceleration (a) * Time (t)) = 10 + (7 * 10) = 10 + 70 = 80 m/s

Therefore, in case c), the trolleybus had an acceleration of 7 m/s^2 and acquired a final velocity of 80 m/s.

Summary

In summary, the trolleybus had the following accelerations and final velocities in each case: a) Distance: 120 m - Acceleration: 11 m/s^2 - Final velocity: 120 m/s

b) Distance: 100 m - Acceleration: 9 m/s^2 - Final velocity: 100 m/s

c) Distance: 80 m - Acceleration: 7 m/s^2 - Final velocity: 80 m/s