Question

Глубину моря под кораблем измеряют с помощью эхолокатора. В одном месте посланный сигнал возвращается через 2,5 с, а в другом- через второе большее время. На сколько глубина моря во втором месте больше, чем в первом? Если скорость звука в воде 1530 м/с

Answer 1

S=V*t

Если сигнал возвращается за 2.5 с, значит он проходит два расстояния за 2.5 с (от лодки до дна и обратно) => от лодки до дна он доходит за 2.5/2=1.25 с

В первом случае: S=1530*1.25=1912.5 м

Во втором случае: t=2.5*3/2=3.75 c

S=1530*3.75=5737.5 м

Тогда разница между глубинами равна: S=5737.5-1912.5=3825 м

Answer 2

Measurement of Sea Depth using an Echo Sounder

To measure the depth of the sea beneath a ship, an echo sounder, also known as an echolocator, is commonly used. This device works by emitting a sound signal, which travels through the water and reflects off the seafloor. By measuring the time it takes for the signal to return, the depth of the sea can be determined.

In the given scenario, the sound signal sent from the ship returns after 2.5 seconds in one location and after a longer time in another location. We are asked to determine the difference in depth between these two locations.

Calculation of the Difference in Depth

To calculate the difference in depth between the two locations, we need to consider the speed of sound in water. The speed of sound in water is approximately 1530 m/s.

Let's assume that the sound signal travels at a constant speed in both locations. In the first location, the sound signal travels to the seafloor and back in 2.5 seconds. Therefore, the total distance traveled by the sound signal in the first location can be calculated as follows:

Distance = Speed × Time = 1530 m/s × 2.5 s = 3825 meters

In the second location, the sound signal takes a longer time to return. Let's denote this time as t. The total distance traveled by the sound signal in the second location can be calculated as follows:

Distance = Speed × Time = 1530 m/s × t

Since the distance traveled in the second location is greater than in the first location, we can set up the following equation:

1530 m/s × t > 3825 meters

To find the difference in depth, we need to determine the value of t that satisfies this inequality. Solving for t, we have:

t > 3825 meters / 1530 m/s t > 2.5 seconds

Therefore, the depth in the second location is greater than in the first location by at least 2.5 seconds.

Conclusion

Based on the given information, the depth of the sea in the second location is greater than in the first location by at least 2.5 seconds. However, without additional information, we cannot determine the exact difference in depth between the two locations.

Please note that the provided sources did not directly address the specific scenario described in the question. However, the information presented is based on general knowledge of echo sounders and the speed of sound in water.

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