Question

Сколько килограммов воды вытесняет плавающий деревянный брус длиной 2 м, шириной 30 см и высотой 20 см? Плотность бруса 600 кг/м3. Ответ округлите до десятых.

Answer 1

решение такое:

Дано:

а=3м

б=30см=0,3м

c=20см=0,2м

p=600кг/м3

решение:

Найдем обьем:V=abc=3м*0,3м*0,2м=0,18м3

Найдем массу: m=pV=600кг/м3*0,18м3=108кг

Answer 2

Calculation of the Volume of the Wooden Block

To determine the amount of water displaced by the floating wooden block, we first need to calculate the volume of the block. The volume of a rectangular block can be calculated by multiplying its length, width, and height.

Given: - Length of the block = 2 m - Width of the block = 30 cm = 0.3 m - Height of the block = 20 cm = 0.2 m

The volume of the block can be calculated as follows:

Volume = Length x Width x Height = 2 m x 0.3 m x 0.2 m = 0.12 cubic meters

Calculation of the Weight of the Displaced Water

To calculate the weight of the displaced water, we need to multiply the volume of the water by its density. The density of water is approximately 1000 kg/m^3.

Given: - Density of water = 1000 kg/m^3

Weight of the displaced water can be calculated as follows:

Weight = Volume x Density = 0.12 cubic meters x 1000 kg/m^3 = 120 kg

Therefore, the floating wooden block displaces approximately 120 kilograms of water.

Please note that the answer has been rounded to the nearest tenth as requested.