Question

В В сосуде объёмом v =2.1 л находится кислород массой 8 г при давлении 200 как. Какова его температура?

Answer 1

Решение на фото.................

Answer 2

Calculating the Temperature of Oxygen Gas in a 2.1 L Container

To calculate the temperature of the oxygen gas in the 2.1 L container, we can use the ideal gas law equation:

PV = nRT

Where: - P = pressure (in atm) - V = volume (in liters) - n = number of moles of gas - R = ideal gas constant (0.0821 L·atm/mol·K) - T = temperature (in Kelvin)

Given: - Volume (V) = 2.1 L - Mass of oxygen (m) = 8 g - Pressure (P) = 200 kPa

First, we need to calculate the number of moles of oxygen using the mass and molar mass of oxygen.

Calculating the Number of Moles of Oxygen

The molar mass of oxygen (O2) is approximately 32 g/mol.

The number of moles (n) can be calculated using the formula: n = mass / molar mass

Substituting the given values: n = 8 g / 32 g/mol n = 0.25 mol

Converting Pressure to atm

The given pressure is in kilopascals (kPa), so we need to convert it to atmospheres (atm) for use in the ideal gas law equation.

1 atm = 101.325 kPa.

Converting the given pressure: P = 200 kPa / 101.325 P ≈ 1.97 atm

Calculating the Temperature

Now, we can rearrange the ideal gas law equation to solve for temperature: T = (P * V) / (n * R)

Substituting the given values: T = (1.97 atm * 2.1 L) / (0.25 mol * 0.0821 L·atm/mol·K) T ≈ 20 K

Therefore, the temperature of the oxygen gas in the 2.1 L container is approximately 20 Kelvin.