Question

Велосипедист движется под уклон с ускорением 0,3м/с в кубе.Какую скорость преобретает велосепидист через 12с,если его начальная скорость была 4 м/с?

Answer 1

A=0.3 t=12 v0=4  v=v0+a*t   v=4+0.3*12=7.6

Answer 2

Calculating the Cyclist's Speed

To calculate the cyclist's speed after 12 seconds, we can use the following kinematic equation:

final velocity = initial velocity + (acceleration * time)

Given: - Initial velocity (u) = 4 m/s - Acceleration (a) = 0.3 m/s^3 - Time (t) = 12 s

We can substitute these values into the equation to find the final velocity:

final velocity = 4 m/s + (0.3 m/s^3 * 12 s)

final velocity = 4 m/s + 3.6 m/s

final velocity = 7.6 m/s

Therefore, the cyclist's speed after 12 seconds, given an initial velocity of 4 m/s and an acceleration of 0.3 m/s^3, is 7.6 m/s.