Question

Ребенок раскачивается на веревочных качелях. При максимальном удалении от положения равновесия его центр масс поднимается на 80 см. Максимальная скорость движения ребенка равна?

Answer 1

h=0.8   v=?

m*g*h=m*v²/2      v=√(2*g*h)=√(2*10*0.8)=4 м/с

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Answer 2

Calculation of Maximum Speed

To calculate the maximum speed of the child on the rope swing, we can use the principle of conservation of mechanical energy. At the highest point of the swing, when the child is farthest from the equilibrium position, all of the potential energy is converted into kinetic energy.

The potential energy at the highest point is given by the formula:

Potential Energy = Mass × Gravity × Height

In this case, the height is given as 80 cm, which is equivalent to 0.8 meters. We need to convert this height to meters to match the units of the other variables.

Using the formula for potential energy, we can calculate the mass of the child. However, we don't have enough information to determine the mass of the child. Therefore, we cannot calculate the exact maximum speed of the child on the rope swing without knowing the mass.

If you have any additional information or if there's anything else I can help you with, please let me know!