Question

S(x)=12+5t-9t³ найти скорость движения в момент времени t=1сек.

Answer 1

Чтобы найти скорость берем производную. s'(x)=5-27x^2= и вставим t. 5-27=-22. Тут не должно быть минуса так что 22 м/с

Answer 2

Calculating Velocity at a Specific Time

To find the velocity at a specific time, we can differentiate the given function S(t) with respect to time t to obtain the expression for velocity.

The given function is: S(t) = 12 + 5t - 9t³

Differentiating the Function

To find the velocity, we need to differentiate the function S(t) with respect to time t. The derivative of S(t) with respect to t gives us the velocity function v(t).

The derivative of S(t) with respect to t is denoted as S'(t) or v(t).

The derivative of the function S(t) is: S'(t) = 5 - 27t²

Finding the Velocity at t = 1 second

Now, we can find the velocity at the specific time t = 1 second by substituting t = 1 into the velocity function S'(t).

Substituting t = 1 into the velocity function: S'(1) = 5 - 27(1)² S'(1) = 5 - 27 S'(1) = -22

Conclusion

The velocity of the object at t = 1 second is -22 units per time, where the units depend on the original units of the function S(t).