Question

Чему равен ежесекундный расход воды гидростанции, если ее полезная мощность 8*10^7 Вт, КПД станции равен 80%,а высота плотины 10м?

Answer 1

Η = Nпол./Nзатр ⇒ Nзатр = Nпол/η
Nзатр = A/t; A = ΔEпотенц = mgH; m = ρV ⇒ Nзатр = ρVgH/t
Nпол/η = ρVgH/t ⇒ V/t = Nпол/ηρgH
Считая плотность воды за 1000 кг/м³ получаем:
V/t = 8·10⁷/(0,8·10³·10·10) = 1000 м³/сек.

Ответ: 1000 кубометров воды в секунду.

Answer 2

Calculation of the Flow Rate of Water at a Hydropower Station

To calculate the flow rate of water at a hydropower station, we can use the formula:

Flow rate (Q) = Power (P) / (Density (ρ) * Acceleration due to gravity (g) * Head (h))

Given the following information: - Power (P) = 8 * 10^7 W (watts) - Efficiency (η) = 80% = 0.8 - Head (h) = 10 m (meters)

We need to find the flow rate (Q).

First, let's calculate the power output of the hydropower station, taking into account the efficiency:

Power output = Power * Efficiency

Power output = 8 * 10^7 W * 0.8

Power output = 6.4 * 10^7 W

Now, we can substitute the values into the flow rate formula:

Flow rate (Q) = Power output / (Density * Acceleration due to gravity * Head)

The density of water (ρ) is approximately 1000 kg/m^3, and the acceleration due to gravity (g) is approximately 9.8 m/s^2.

Flow rate (Q) = 6.4 * 10^7 W / (1000 kg/m^3 * 9.8 m/s^2 * 10 m)

Simplifying the equation:

Flow rate (Q) = 6.4 * 10^7 / (1000 * 9.8 * 10) m^3/s

Flow rate (Q) = 6.4 * 10^7 / 98000 m^3/s

Calculating the value:

Flow rate (Q) ≈ 653.06 m^3/s

Therefore, the approximate flow rate of water at the hydropower station is 653.06 cubic meters per second.