Question

Башенный кран равномерноподнимает груз массой 0,5 т на высоту 30 м за 2 мин сила тока в электродвигателе равна 16,5 А при напряжении 220В определите КПД КРАНА. УМОЛЯЮ. ПОМОГИТЕ

Answer 1

N=Aполезное/Аполное=mgh/UIt
[n]=(кг*м/с^2*м)/(В*А*с)=(Н*м)/Дж=Дж/Дж=1
{n}=(0,5*1000*10*30)/(220*16,5*1/30)=...
n=…=…*100%

Answer 2

Calculation of Efficiency (КПД) of the Crane

To determine the efficiency (КПД) of the crane, we need to calculate the input power and the output power.

The input power (P_in) can be calculated using the formula:

P_in = V * I

Where: - V is the voltage (220V) - I is the current (16.5A) Substituting the given values: P_in = 220V * 16.5A = 3630W

The output power (P_out) can be calculated using the formula:

P_out = m * g * h / t

Where: - m is the mass of the load (0.5t) - g is the acceleration due to gravity (9.8 m/s²) - h is the height (30m) - t is the time taken to lift the load (2min = 120s) Substituting the given values: P_out = 0.5t * 9.8 m/s² * 30m / 120s = 3.675W

Now, we can calculate the efficiency (КПД) of the crane using the formula:

Efficiency (КПД) = P_out / P_in * 100%

Substituting the calculated values: Efficiency (КПД) = 3.675W / 3630W * 100% ≈ 0.101%

Therefore, the efficiency (КПД) of the crane is approximately 0.101%.