Question

Какое количество энергии выделит вода массой 5 кг при охлаждении от 100 до 0*С

Answer 1

Q=c * m *дельтаt 
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Q=4200 * 5 * 100=2100000Дж=2100кДж=2,1МДж  

Answer 2

Calculation of Energy Released by Cooling Water

To calculate the amount of energy released by cooling water, we can use the formula:

Q = m * c * ΔT

Where: - Q is the amount of energy released (in joules) - m is the mass of water (in kilograms) - c is the specific heat capacity of water (in joules per kilogram per degree Celsius) - ΔT is the change in temperature (in degrees Celsius)

In this case, we have: - m = 5 kg (mass of water) - ΔT = 100°C - 0°C = 100°C (change in temperature)

To find the specific heat capacity of water, we can refer to a reliable source. According to the specific heat capacity of water is approximately 4.18 joules per gram per degree Celsius.

Converting the mass of water from kilograms to grams: - m = 5 kg * 1000 g/kg = 5000 g

Converting the specific heat capacity from joules per gram per degree Celsius to joules per kilogram per degree Celsius: - c = 4.18 J/g°C * (1 kg / 1000 g) = 0.00418 J/g°C * (1 kg / 1000 g) = 0.00418 J/kg°C

Now we can calculate the amount of energy released:

Q = m * c * ΔT = 5000 g * 0.00418 J/kg°C * 100°C = 2090 J

Therefore, the water with a mass of 5 kg will release approximately 2090 joules of energy when cooled from 100°C to 0°C.

Please note that the specific heat capacity of water may vary slightly depending on the temperature range and other factors. The value used in this calculation is an approximation.

Conclusion

The water with a mass of 5 kg will release approximately 2090 joules of energy when cooled from 100°C to 0°C.

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