Question

Какое количество воды можно вскипятить, затратив 0,5 кг дров, если КПД кипятильника 30 %, а начальная температура воды 10 0С?

Answer 1

Q=q*m    Q=10^4*0,5=5000 Дж 
Q=c*m*дельта T=q*m 
cm(tк-tнач.)=5000 
m=Q/(с(tк-tнач))

c= 4,2 кДж/(кг*К) 
m=5000/(4200*(100-10) =0,01кг 

вроде так должно быть

Answer 2

Calculating the Amount of Water Boiled Using 0.5 kg of Wood

To calculate the amount of water that can be boiled using 0.5 kg of wood, given the efficiency of the stove and the initial temperature of the water, we can use the following formula:

Amount of water boiled = (Energy content of wood * Efficiency of the stove) / (Specific heat capacity of water * (Final temperature - Initial temperature))

Where: - Energy content of wood is the energy released by burning 1 kg of wood, typically around 3000 kcal/kg. - Efficiency of the stove is given as 30%. - Specific heat capacity of water is approximately 1 calorie/gram °C. - Initial temperature of water is 10°C.

Calculation

Using the given values: - Energy content of 0.5 kg of wood = 0.5 kg * 3000 kcal/kg = 1500 kcal - Efficiency of the stove = 30% - Specific heat capacity of water = 1 calorie/gram °C - Initial temperature of water = 10°C

We can calculate the amount of water boiled using the formula:

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