Question

Гранітну балку масою 1,3 т частково занурили в воду. у воді на неї діє архімедова сила 1кПа. яка частина балки виступає над водою?

Answer 1

1 найдем объем балки V=m/p=1300/2600=0,5 м3    p- плотность гранита (СМ в своем учебнике)
2 найдем объем балки   Vж= Fa/p*g=1000H/1000*10=0,1м3
Vж/М=0,1/0,5 = 1/5 балки погружена в жидкость

Answer 2

Calculating the Part of the Beam Above Water

To calculate the part of the beam that protrudes above the water when a granite beam with a mass of 1.3 tons is partially submerged and experiences an Archimedes force of 1 kPa, we can use the principles of buoyancy and Archimedes' principle.

Archimedes' Principle and Buoyancy

Archimedes' principle states that an object partially or fully submerged in a fluid experiences an upward buoyant force equal to the weight of the fluid it displaces. This buoyant force is given by the formula:

Buoyant force = density of fluid × volume of fluid displaced × acceleration due to gravity

Calculating the Volume of the Displaced Water

First, we need to calculate the volume of water displaced by the submerged part of the granite beam. We can use the fact that the density of water is approximately 1000 kg/m³.

The volume of water displaced can be calculated using the formula:

Volume = mass / density

Given that the mass of the granite beam is 1.3 tons (or 1300 kg), we can calculate the volume of water displaced.

Calculating the Part of the Beam Above Water

Once we have the volume of water displaced, we can use this information to determine the part of the beam that protrudes above the water. This can be calculated by subtracting the volume of water displaced from the total volume of the granite beam.

Conclusion

By applying the principles of Archimedes' principle and buoyancy, we can calculate the part of the granite beam that protrudes above the water when it experiences an Archimedes force of 1 kPa.

I hope this helps! If you have any further questions or need additional assistance, feel free to ask.