Question

Тепловая машина за цикл получает от нагревателя количество теплоты 100 Дж и отдаёт холодильнику 60 Дж чему равен КПД машины Можно дано и решение, пожалуйста

Answer 1

Формула
Дано:
КП/Д=(1-2)/1=1=100=2=60
100/60=1,6-1-1=0,4 переводим - 40 процентов
_______________________________
Puply

Answer 2

N=(100-60)/100=0.4  (40%)

Answer 3

Calculating the Efficiency of a Heat Engine

To calculate the efficiency of a heat engine, we can use the formula:

Efficiency (η) = 1 - (Qc / Qh)

Where: - Qh is the heat absorbed from the hot reservoir (in this case, the heater). - Qc is the heat rejected to the cold reservoir (in this case, the refrigerator).

Given: - Qh = 100 J - Qc = 60 J

Calculating Efficiency

Using the formula, we can calculate the efficiency of the heat engine:

Efficiency (η) = 1 - (60 / 100) Efficiency (η) = 1 - 0.6 Efficiency (η) = 0.4

So, the efficiency of the heat engine is 40%.

This calculation is based on the principles of thermodynamics and the definition of efficiency for heat engines.