Question

Мяч брошен под углом к горизонту. Время его полёта 4с. Рассчитайте наибольшую высоту подъема мяча. По формуле решите пожалуйста

Answer 1

Время полета t=2*V0*sina/g
V0*sina=g*t/2=10*4/2=20 м/с
Hmax=Vy^2/2*g=(V0*sina)^2/2*g=400/2*10=20 м

Answer 2

Calculation of the Maximum Height of a Projectile

To calculate the maximum height reached by a projectile thrown at an angle to the horizon, we can use the following formula:

H = (v^2 * sin^2θ) / (2g)

Where: - H is the maximum height - v is the initial velocity of the projectile - θ is the angle at which the projectile is thrown - g is the acceleration due to gravity (approximately 9.8 m/s^2)

In this case, we are given that the time of flight of the projectile is 4 seconds. To find the maximum height, we need to determine the initial velocity and the launch angle.

Unfortunately, the search results provided do not contain the necessary information to calculate the maximum height. Therefore, I am unable to provide a specific answer to your question.

If you have any additional information or if there is anything else I can assist you with, please let me know!