Question

Температура нагревателя идеального теплового двигателя 425 К, а холодильника - 300 К. Двигатель получает от нагревателя 4 ∙ 104 Дж теплоты. Рассчитать работу, совершаемую рабочим телом двигателя.

Answer 1

Рассчитать работу, совершаемую рабочим телом двигателя.

кпд=1-300/425=0.30 (30%)

А=Q*кпд=4*10^4*0.30=12 кДж

Answer 2

Calculation of Work Done by the Engine

To calculate the work done by the working substance in the engine, we can use the formula:

Work = Heat Input - Heat Output

Given: - Temperature of the heater (nagrevatel) = 425 K - Temperature of the refrigerator (kholodilnik) = 300 K - Heat input from the heater = 4 * 10^4 J

To calculate the heat output, we need to find the efficiency of the engine. The efficiency of an ideal heat engine is given by the formula:

Efficiency = 1 - (Tc/Th)

Where: - Tc is the temperature of the cold reservoir (refrigerator) - Th is the temperature of the hot reservoir (heater)

Let's calculate the efficiency:

Efficiency = 1 - (300/425) = 1 - 0.7059 = 0.2941

Now, we can calculate the heat output using the formula:

Heat Output = Efficiency * Heat Input

Heat Output = 0.2941 * 4 * 10^4 J = 1.1764 * 10^4 J

Finally, we can calculate the work done by the working substance in the engine using the formula:

Work = Heat Input - Heat Output

Work = 4 * 10^4 J - 1.1764 * 10^4 J = 2.8236 * 10^4 J

Therefore, the work done by the working substance in the engine is 2.8236 * 10^4 J.

Please note that the calculations provided above are based on the information given in the question and may not take into account other factors or assumptions that could affect the accuracy of the result.