Question

Найти среднюю квадратичную скорость молекулы водорода при температуре 27 градусов цельсия .

Answer 1

Дано T=300 К    V-?   M=0,002 кг/моль
по формуле V = √ 3*R*T/M=√3*8,31*300/0,002=1933,8 м/с=1,9 км/с

Answer 2

Calculation of the Average Square Velocity of Hydrogen Molecules at 27 degrees Celsius

To calculate the average square velocity of hydrogen molecules at a temperature of 27 degrees Celsius, we can use the root mean square (RMS) velocity formula. The RMS velocity is a measure of the average speed of gas molecules in a sample.

The formula for calculating the RMS velocity is:

v_rms = sqrt((3 * k * T) / m)

Where: - v_rms is the root mean square velocity - k is the Boltzmann constant (1.38 x 10^-23 J/K) - T is the temperature in Kelvin (27 degrees Celsius = 27 + 273.15 = 300.15 K) - m is the molar mass of hydrogen (2.016 g/mol)

Let's substitute the values into the formula and calculate the average square velocity.

v_rms = sqrt((3 * 1.38 x 10^-23 J/K * 300.15 K) / 2.016 g/mol)

Converting the molar mass from grams to kilograms:

v_rms = sqrt((3 * 1.38 x 10^-23 J/K * 300.15 K) / 0.002016 kg/mol)

Calculating