Question

Какое время потребуется подъемнику с мощностью двигателя 2 кВт , чтобы поднять гауз массой 400 кг на высоту 16 м? КПД подъемника равен 80%

Answer 1

Аполезн=mgh=400*10*16=64 000 Дж;

Азатрач=Nt=2 000*t

КПД=Апол/Азатрач=0,8; Азатр=Апол/0,8

2 000*t*0,8=64 000

2*0,8*t=64

t=64/1,6=640/16=40 cек.

m=400кг; h=16м; N=2000 Вт; КПД=80%=80/100=0,8; t - ?

Answer 2

Calculating Time Required for Lifting a Load

To calculate the time required for the lift, we can use the formula:

Time = Work / Power

Where: - Work is the work done, which is equal to the force applied multiplied by the distance moved. - Power is the power of the lifting mechanism. - The efficiency (η) of the lifting mechanism is given as 80% or 0.80.

Calculating Work Done

The work done in lifting the load can be calculated using the formula:

Work = Force × Distance

Given: - Force (F) = 400 kg (mass) × 9.81 m/s² (acceleration due to gravity) = 3924 N - Distance (d) = 16 m

So, Work = 3924 N × 16 m

Calculating Time

Now, using the formula Time = Work / (Power × Efficiency), we can calculate the time required for the lift.

Substituting the values: - Work = 3924 N × 16 m - Power = 2 kW = 2000 W - Efficiency (η) = 80% = 0.80

We get: Time = (3924 N × 16 m) / (2000 W × 0.80)

Calculating this gives us the time required for the lift.

Result

The time required for the lift is calculated to be approximately 31.08 seconds.

This calculation is based on the given parameters and the formula for work, power, and efficiency of the lifting mechanism.