Question

За какое время нагреется 0 С° до кипения 10 кг воды на электроплитке с КПД 90% при силе тока 2 А и напряжении в сети 220 В

Answer 1

КПД=(с*m*ΔT)/(I*U*Δt)

Δt=(c*m*ΔT)/(I*U*КПД)

с=4200

m=10

ΔT=100

КПД=0,9

I=2

U=220

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Answer 2

Calculation of Time to Heat Water

To calculate the time it takes to heat 10 kg of water from 0°C to its boiling point, we need to consider the power, efficiency, current, and voltage of the electric stove.

Given: - Mass of water (m): 10 kg - Initial temperature (T1): 0°C - Final temperature (T2): 100°C (boiling point of water) - Efficiency (η): 90% - Current (I): 2 A - Voltage (V): 220 V

The formula to calculate the time it takes to heat water is:

t = (m * ΔT) / (P * η)

Where: - t is the time in seconds - m is the mass of water in kg - ΔT is the change in temperature in °C (T2 - T1) - P is the power in watts (P = V * I)

Let's calculate the time using the given values:

1. Calculate the power: P = V * I = 220 V * 2 A = 440 W

2. Calculate the change in temperature: ΔT = T2 - T1 = 100°C - 0°C = 100°C

3. Calculate the time: t = (m * ΔT) / (P * η) = (10 kg * 100°C) / (440 W * 0.9) = 227.27 seconds

Therefore, it will take approximately 227.27 seconds to heat 10 kg of water from 0°C to its boiling point on an electric stove with a 90% efficiency, a current of 2 A, and a voltage of 220 V.

Please note that the above calculation assumes ideal conditions and does not account for heat losses or other factors that may affect the actual heating time.