Question

При напряжении 220В в лампочке проходит ток 360мА в течение получаса. Какую работу при этом выполняет электрическое поле?

Answer 1

A=P*t
P=I*U=220*0.36=79.2Вт
A=1800*79.2=142560Дж

Answer 2

Electrical Work Done by the Electric Field

When a current flows through a light bulb at a voltage of 220V for half an hour, the electrical work done by the electric field can be calculated using the formula:

Work (W) = Voltage (V) × Current (I) × Time (t)

Given: - Voltage (V) = 220V - Current (I) = 360mA (or 0.36A) - Time (t) = 0.5 hours

Using the formula, the work done by the electric field can be calculated as follows:

W = V × I × t W = 220V × 0.36A × 0.5h W = 39.6J

Therefore, the electric field does 39.6 joules of work during this time period.

This work is done in the form of converting electrical energy into light and heat energy within the light bulb, as well as overcoming the resistance in the circuit.