Question

Через алюминиевый проводник длиной 70 см и площадью поперечного сечения 0,7 мм2 протекает ток силой 0,5 А. Каково напряжение на концах этого проводника?какое количество электричества проходит по нему за 1 минуту?

Answer 1

$\mathcal U=\mathcal {IR}=\mathcal I \dfrac{\rho l}{S} =0,5* \dfrac{0,028*0,7}{0,7}=0,014\ (B)\\ \mathcal I= \dfrac{q}{t};\ q=\mathcal It=0,5*60=30\ (K_\Lambda)$

Answer 2

Calculation of Voltage and Electric Charge

To calculate the voltage and electric charge in the given scenario, we need to use the formulas related to Ohm's Law and electric charge.

The formula for voltage is:

Voltage (V) = Current (I) x Resistance (R)

The formula for electric charge is:

Electric Charge (Q) = Current (I) x Time (t)

Given information: - Length of the aluminum conductor (l) = 70 cm = 0.7 m - Cross-sectional area of the conductor (A) = 0.7 mm² = 0.7 x 10⁻⁶ m² - Current flowing through the conductor (I) = 0.5 A - Time (t) = 1 minute = 60 seconds

To calculate the resistance (R), we can use the formula:

Resistance (R) = Resistivity (ρ) x (Length (l) / Cross-sectional Area (A))

The resistivity of aluminum (ρ) is approximately 2.65 x 10⁻⁸ Ω·m.

Let's calculate the resistance first:

Resistance (R) = (2.65 x 10⁻⁸ Ω·m) x (0.7 m / 0.7 x 10⁻⁶ m²)

Calculating the resistance gives us:

Resistance (R) = 2.65 x 10⁻⁸ Ω·m

Now, we can calculate the voltage using Ohm's Law:

Voltage (V) = Current (I) x Resistance (R)

Voltage (V) = (0.5 A) x (2.65 x 10⁻⁸ Ω·m)

Calculating the voltage gives us:

Voltage (V) = 1.325 x 10⁻⁸ V

Therefore, the voltage on the ends of the conductor is approximately 1.325 x 10⁻⁸ V.

Next, let's calculate the electric charge using the formula:

Electric Charge (Q) = Current (I) x Time (t)

Electric Charge (Q) = (0.5 A) x (60 s)

Calculating the electric charge gives us:

Electric Charge (Q) = 30 C

Therefore, the amount of electric charge passing through the conductor in 1 minute is 30 C.

Please note that the values calculated here are approximate due to rounding.