Question

Тело массой 5 кг свободно падает с высоты 50 м. Определить кинетическую и потенциальную энергию в середине пути.

Answer 1

Mgh/2=mv^2/2

Кинетическая энергия равна 1250дж

Потенциальная равна той же величине mgh/2

Answer 2

Calculation of Kinetic and Potential Energy

To determine the kinetic and potential energy of a body with a mass of 5 kg freely falling from a height of 50 m, we can use the formulas for kinetic energy and potential energy.

Kinetic Energy is the energy possessed by an object due to its motion. It can be calculated using the formula:

KE = (1/2) * m * v^2

where KE is the kinetic energy, m is the mass of the object, and v is the velocity of the object.

Potential Energy is the energy possessed by an object due to its position or height above the ground. It can be calculated using the formula:

PE = m * g * h

where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity (approximately 9.8 m/s^2), and h is the height of the object above the ground.

Let's calculate the kinetic and potential energy of the body in the middle of its fall.

Calculation:

Given: - Mass of the body (m) = 5 kg - Height of the fall (h) = 50 m

To find the kinetic and potential energy in the middle of the fall, we need to determine the velocity of the body at that point. Since the body is freely falling, we can use the equations of motion to find the velocity.

Using the equation of motion for free fall:

v^2 = u^2 + 2 * g * h

where v is the final velocity, u is the initial velocity (which is 0 in this case), g is the acceleration due to gravity, and h is the height of the fall.

Substituting the given values:

v^2 = 0^2 + 2 * 9.8 * 50

v^2 = 980

Taking the square root of both sides:

**v = √980 ≈