Question

Чему равна масса закиси азота NO2 в баллоне емкостью 0,08 м3 при температуре 280 К и давлении 1,4•105 Па?

Answer 1

Дано:
V=0,08м³
p=1,4·10⁵Па
M(NO₂)=0,046 кг/моль
T=280К
R=8,31Дж/(моль·К)
Найти:
m=?
Решение:
pV=mRT/M
mRT=pVM
m = pVM/RT
m=1,4·10⁵Па×0,08м³×0,046кг/моль /(8,31Дж/(моль·кг) ×280К) = 0,22кг
m=0,22кг

Answer 2

Calculation of the Mass of Nitrogen Dioxide (NO2) in the Cylinder

To calculate the mass of nitrogen dioxide (NO2) in the cylinder, we need to use the ideal gas law equation:

PV = nRT

Where: P = Pressure of the gas (in Pascals) V = Volume of the gas (in cubic meters) n = Number of moles of the gas R = Ideal gas constant (8.314 J/(mol·K)) T = Temperature of the gas (in Kelvin)

Given: Volume (V) = 0.08 m^3 Temperature (T) = 280 K Pressure (P) = 1.4 × 10^5 Pa

First, let's convert the given pressure from Pascals to atmospheres (atm) since the ideal gas constant (R) is commonly expressed in terms of atm:

1 atm = 101325 Pa

1 atm ≈ 101325 Pa

1 Pa ≈ 9.86923 × 10^-6 atm

1.4 × 10^5 Pa ≈ 1.4 × 10^5 × 9.86923 × 10^-6 atm ≈ 1.3787 atm

Now, we can calculate the number of moles (n) using the ideal gas law equation:

PV = nRT

n = PV / RT

n = (1.3787 atm) × (0.08 m^3) / [(8.314 J/(mol·K)) × (280 K)]

n ≈ 0.0048 moles

To calculate the mass of NO2, we need to know the molar mass of NO2, which is the sum of the atomic masses of nitrogen (N) and two oxygen (O) atoms:

Molar mass of N = 14.01 g/mol Molar mass of O = 16.00 g/mol

Molar mass of NO2 = (14.01 g/mol) + 2 × (16.00 g/mol) ≈ 46.01 g/mol

Finally, we can calculate the mass of NO2 using the number of moles (n) and the molar mass of NO2:

Mass of NO2 = n × Molar mass of NO2

Mass of NO2 ≈ 0.0048 moles × 46.01 g/mol ≈ 0.2208 g

Therefore, the mass of nitrogen dioxide (NO2) in the cylinder is approximately 0.2208 grams.