Question

Маятник совершил 40 колебаний за 4 минуты .найдите их период и частоту

Answer 1

Дано:
n=40
t=4мин=240сек.
T-?  
υ-?  

Решение
T=t/n=240/40=6 cек.
υ=n/t=40/240= ~0,16 Гц.

Answer 2

Calculation of Period and Frequency of a Pendulum

To find the period and frequency of a pendulum, we need to know the number of oscillations and the time it takes to complete those oscillations. In this case, the pendulum completed 40 oscillations in 4 minutes.

Period is the time it takes for one complete oscillation of the pendulum. It can be calculated by dividing the total time by the number of oscillations. In this case, the period can be calculated as:

Period = Total time / Number of oscillations

Substituting the given values:

Period = 4 minutes / 40 oscillations

To calculate the period, we need to convert the time to seconds, as the SI unit for time is seconds. There are 60 seconds in a minute, so:

Period = (4 minutes * 60 seconds) / 40 oscillations

Simplifying the equation:

Period = 240 seconds / 40 oscillations

Period = 6 seconds / oscillation

Therefore, the period of the pendulum is 6 seconds.

Frequency is the number of oscillations per unit of time. It is the reciprocal of the period and can be calculated as:

Frequency = 1 / Period

Substituting the value of the period:

Frequency = 1 / 6 seconds

Therefore, the frequency of the pendulum is 1/6 Hz.

Please note that the above calculations are based on the assumption that the pendulum oscillates with a constant period and frequency throughout the 40 oscillations.