Question

Температура воды 0 градусов цельсия,ее масса 2 кг.Какое количество теплоты выделяет вода при замерзании?удельная теплота плавления льда 3,4 уможить на 10^5 дж/кг.Напишите пожалуйста с дано

Answer 1

Дано:
m = 2 кг
L = 340000 Дж:кг

Решение: Q = mL

Q = 2 x 340000 = 640000 Дж
Ответ: 0.64 МДж

Answer 2

Calculation of Heat Released during Freezing of Water

To calculate the amount of heat released when water freezes at 0 degrees Celsius, we need to use the specific latent heat of fusion of ice, which is given as 3.4 x 10^5 J/kg.

Given: - Temperature of water = 0 degrees Celsius - Mass of water = 2 kg - Specific latent heat of fusion of ice = 3.4 x 10^5 J/kg

To find the amount of heat released, we can use the formula:

Q = m * Lf

Where: - Q is the amount of heat released (in joules) - m is the mass of the water (in kilograms) - Lf is the specific latent heat of fusion of ice (in joules per kilogram)

Substituting the given values into the formula, we get:

Q = 2 kg * (3.4 x 10^5 J/kg)

Calculating this, we find:

Q = 6.8 x 10^5 J

Therefore, when 2 kg of water freezes at 0 degrees Celsius, it releases approximately 6.8 x 10^5 joules of heat.

Please note that this calculation assumes that the water is pure and that there are no other factors affecting the freezing process.

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