Question

Два сопротивления R1 = 2 кОм и R2 соединены последовательно и подключены в сеть с напряжением U = 200 В. На сопротивлении R1 выделяется мощность P = 5 Вт. Найти R2

Answer 1

R1 = 2 кОм =2000 Ом, R2,  U = 200 В,  P = 5 Вт. R2-?
Найдем напряжение на R1.  P=I1U1. I1=U1/R1, P=U1²/R1, U1=√(P*R1,U1=√5*2000=100 В. Значит U2=U-U1=100 В. R2=U2/I2.
При последовательном соединении  I2=I1=I.I=P/U1, I=5/100=0,05 А. R2=100/0,05=2000 Ом.
Ответ:
R2=2000 Ом.

Answer 2

Calculation of R2 in a Series Circuit

To find the value of R2 in a series circuit with resistances R1 and R2, we can use the formula for total resistance in a series circuit:

R_total = R1 + R2

In this case, we are given that R1 = 2 kΩ (kilohms) and the total voltage across the circuit is U = 200 V (volts). We are also given that the power dissipated by R1 is P = 5 W (watts).

To find R2, we need to calculate the current flowing through the circuit using Ohm's Law:

I = U / R_total

Once we have the current, we can use the power formula to find the resistance R2:

P = I^2 * R2

Let's calculate R2 step by step:

1. Calculate the total resistance R_total: - R1 = 2 kΩ = 2000 Ω - R_total = R1 + R2

2. Calculate the current I: - I = U / R_total

3. Calculate R2 using the power formula: - P = I^2 * R2

Let's perform the calculations:

1. Calculate the total resistance R_total: - R1 = 2000 Ω - R_total = R1 + R2

2. Calculate