Question

Парциальное давление водяного пара в воздухе при температуре 25 градусов было 2,5кПа.Определить влажность воздуха.

Answer 1

p=2.5*10^3 Па

t=25C

Pнас=3,17*10^3 Па

P\Pнас=2.5*10^3\3.17*10^3=0.79=79%

Ответ:79%

Answer 2

Calculation of Air Humidity

To determine the humidity of the air, we need to know the partial pressure of water vapor in the air at a temperature of 25 degrees Celsius.

Given that the partial pressure of water vapor in the air is 2.5 kPa, we can use the relationship between partial pressure and relative humidity to calculate the air humidity.

The relationship between partial pressure and relative humidity is given by the Clausius-Clapeyron equation:

Pv = P * (RH / 100)

Where: - Pv is the partial pressure of water vapor - P is the total pressure of the air - RH is the relative humidity expressed as a percentage

In this case, we know the partial pressure of water vapor (Pv) is 2.5 kPa and the temperature is 25 degrees Celsius. However, we don't have the total pressure of the air (P) to directly calculate the relative humidity (RH).

To proceed, we need to make some assumptions. The most common assumption is that the total pressure of the air is equal to the atmospheric pressure. At sea level, the average atmospheric pressure is approximately 101.3 kPa.

Using this assumption, we can rearrange the equation to solve for relative humidity:

RH = (Pv / P) * 100

Substituting the given values:

RH = (2.5 kPa / 101.3 kPa) * 100

Calculating this expression, we find that the relative humidity of the air is approximately 2.47%.

Please note that this calculation assumes the total pressure of the air is equal to the atmospheric pressure. In reality, the total pressure of the air can vary depending on factors such as altitude and weather conditions.