Question

Полезная мощность вырабатываемое электростанции равна 60 МВт при этом каждую минуту с ее гребля высотой 30 метров падает вода массой 15 тон чему равен КПд гидроэлектростанция

Answer 1

Дано: 
N = 6*10^7 Вт 
h = 30 м; g = 9.81 м/с^2 
m = 15000 кг 
t = 60 с 
Найти: КПД 
Решение: 
КПД = N*t/A = N*t/(m*g*h) 
P.S. Где-то с данными ошибка, так как КПД < 1!

Answer 2

Calculation of Efficiency of a Hydroelectric Power Plant

To calculate the efficiency of a hydroelectric power plant, we need to know the useful power generated by the plant and the input power, which is the power of the falling water. In this case, the useful power is given as 60 MW, and the mass of water falling every minute is given as 15 tons.

The efficiency (η) of a hydroelectric power plant can be calculated using the formula:

η = (Useful Power / Input Power) * 100%

To find the input power, we need to calculate the potential energy of the falling water.

Calculation of Input Power

The potential energy (PE) of an object is given by the formula:

PE = m * g * h

Where: - m is the mass of the object (in this case, the mass of water falling every minute, which is 15 tons or 15,000 kg) - g is the acceleration due to gravity (approximately 9.8 m/s^2) - h is the height of the object (in this case, the height of the dam, which is 30 meters)

Substituting the given values into the formula, we can calculate the potential energy of the falling water:

PE = 15,000 kg * 9.8 m/s^2 * 30 m

Calculation of Efficiency

Now that we have the useful power and the input power, we can calculate the efficiency of the hydroelectric power plant using the formula mentioned earlier:

η = (Useful Power / Input Power) * 100%

Substituting the given values into the formula, we can calculate the efficiency:

η = (60 MW / Input Power) * 100%

Please note that we need to convert the units appropriately to ensure consistency.