Question

Сколько расплавится льда, взятого при температуре 0 градусов если ему сообщить такое же количество теплоты, которое выделится при конденсации 8 килограмм водяного пара при температуре 100 градусов

Answer 1

Сначала находим количество теплоты которое выделится при конденсации пара:
Q=Lm=2300000 Дж/кг * 8 кг = Дж
Теперь находим массу расплавившегося льда
Q=mu u - это будет лямбда:)
m=Q/u=18 400 000 Дж / 330 000 Дж/кг =55,8 кг

Answer 2

Calculation of the Amount of Heat Required to Melt Ice

To determine how much ice will melt when the same amount of heat is applied as the heat released during the condensation of 8 kilograms of water vapor at 100 degrees Celsius, we can use the equation:

Q = m * L

Where: - Q is the amount of heat (in joules) - m is the mass of the substance (in kilograms) - L is the latent heat of fusion (in joules per kilogram)

In this case, we need to find the mass of ice that will melt, so we can rearrange the equation as follows:

m = Q / L

Now, let's calculate the mass of ice that will melt.

First, we need to find the amount of heat released during the condensation of 8 kilograms of water vapor at 100 degrees Celsius. The latent heat of condensation for water is 2.26 * 10^6 joules per kilogram.

Q = m * L Q = 8 kg * 2.26 * 10^6 J/kg Q = 18.08 * 10^6 J

Now, we can find the mass of ice that will melt when the same amount of heat is applied. The latent heat of fusion for ice is 3 * 10^5 joules per kilogram.

m = Q / L m = 18.08 * 10^6 J / 3 * 10^5 J/kg m = 60.27 kg

Therefore, if the same amount of heat is applied to ice at 0 degrees Celsius as the heat released during the condensation of 8 kilograms of water vapor at 100 degrees Celsius, approximately 60.27 kilograms of ice will melt.

Please note that this calculation assumes ideal conditions and does not take into account any heat losses or other factors that may affect the melting process.