Question

Три проводника с сопротивлением 4,6 и 8 Ом соединены параллельно.В первом проводнике сила тока 15 А. Определите силу тока в каждом из остальных проводников

Answer 1

Поскольку при параллельном соединении напряжение  в сети одинаковое на всех участка. Находим напряжение U=R*I=4*15=60 В
тогда находим силу тока во втором проводнике :
I=60/6=10 A
в последнем:
I=60/8=7,5 А

Answer 2

Calculation of Current in Each Conductor

To determine the current in each of the conductors, we can use the formula for calculating the total resistance in a parallel circuit and then apply Ohm's Law.

The formula for calculating the total resistance in a parallel circuit is:

1/R_total = 1/R1 + 1/R2 + 1/R3

Given the resistances of the three conductors as 4 Ω, 6 Ω, and 8 Ω, we can substitute these values into the formula:

1/R_total = 1/4 + 1/6 + 1/8

Simplifying this equation, we get:

1/R_total = 3/24 + 4/24 + 3/24 = 10/24

Taking the reciprocal of both sides, we find:

R_total = 24/10 = 2.4 Ω

Now that we have the total resistance, we can use Ohm's Law to calculate the current in each conductor.

Ohm's Law states that the current (I) flowing through a conductor is equal to the voltage (V) across the conductor divided by the resistance (R) of the conductor:

I = V/R

In this case, the voltage across each conductor is the same, so we can use the total current (I_total) and the resistance of each conductor to calculate the current in each conductor.

Let's denote the current in the first conductor as I1, the current in the second conductor as I2, and the current in the third conductor as I3.

We are given that the current in the first conductor (I1) is 15 A.

Using Ohm's Law, we can calculate the current in the second conductor (I2) as:

I2 = I_total * (R_total / R2) = 15 A * (2.4 Ω / 6 Ω) = 6 A

Similarly, we can calculate the current in the third conductor (I3) as:

I3 = I_total * (R_total / R3) = 15 A * (2.4 Ω / 8 Ω) = 4.5 A

Therefore, the current in each of the conductors is as follows:

- Current in the first conductor (I1): 15 A - Current in the second conductor (I2): 6 A - Current in the third conductor (I3): 4.5 A