Question

Поезд массой 1500 т увеличил скорость от 5 до 10 м/с в течение 3 мин. Определите силу, сообщающую поезду ускорение.

Answer 1

F=MA
A=(U-Uo)/t
F=1500 000* (10-5)/180=ПРИМЕРНО 41 700 Н
ОТВЕТ:41.7КН

Answer 2

Calculation of the Force

To determine the force that imparts acceleration to the train, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a). In this case, the train has a mass of 1500 tons and undergoes an acceleration from 5 m/s to 10 m/s over a period of 3 minutes.

First, we need to convert the mass of the train from tons to kilograms. Since 1 ton is equal to 1000 kilograms, the mass of the train is 1500 tons * 1000 kg/ton = 1,500,000 kg.

Next, we need to convert the time from minutes to seconds. Since 1 minute is equal to 60 seconds, the time is 3 minutes * 60 seconds/minute = 180 seconds.

Now, we can calculate the acceleration (a) using the formula:

a = (vf - vi) / t

where vf is the final velocity, vi is the initial velocity, and t is the time.

Plugging in the values, we have:

a = (10 m/s - 5 m/s) / 180 s = 5 m/s / 180 s ≈ 0.0278 m/s^2

Finally, we can calculate the force (F) using the formula:

F = m * a

Plugging in the values, we have:

F = 1,500,000 kg * 0.0278 m/s^2 ≈ 41,700 N

Therefore, the force that imparts acceleration to the train is approximately 41,700 Newtons (N).