Question

Помогите пожалуйста!!! Два сосуда, наполненных воздухом при давлениях 0,8 МПа и 0,6 МПа, имеют объемы 3л и 5л соответственно.Сосуды соединили трубкой.Найти установившееся давление в сосудах.

Answer 1

T = const; изотермический процесс;

p1V1 = p2V2;

p1V1 = p1'(V1+V2)

p2V2 = p2'(V1+V2);

p = p1'+p2'

p1' = p1V1/(V1+V2) = (0.8*10^6*3*10^-3)/(8*10^-3) = 300кПа

p2' = p2V2/(V1+V2) = (0.6*10^6*5*10^-3)/(8*10^-3) = 375кПа

p = 675кПа 

Answer 2

Calculation of the Equilibrium Pressure in the Connected Vessels

To find the equilibrium pressure in the connected vessels, we can apply the principle of Pascal's law, which states that when a fluid is in equilibrium, the pressure is the same at all points.

In this case, the connected vessels are filled with air at different pressures: 0.8 MPa and 0.6 MPa, with volumes of 3 liters and 5 liters, respectively.

According to Pascal's law, the pressure in the vessels will equalize when they are connected. Therefore, the equilibrium pressure in the connected vessels will be the same.

Let's denote the equilibrium pressure as P. Since the pressure is the same in both vessels, we can set up the following equation:

P = P1 = P2

Where: - P is the equilibrium pressure in the connected vessels. - P1 is the initial pressure in the first vessel (0.8 MPa). - P2 is the initial pressure in the second vessel (0.6 MPa).

By substituting the given values, we have:

P = 0.8 MPa = 0.6 MPa

Therefore, the equilibrium pressure in the connected vessels is 0.8 MPa.

Please let me know if there is anything else I can help you with!