
Вагон массой 20 тонн двигался со скоростью 0,3 м/с, нагнал вагон массой 30тонн движущийся сл
скоростью 0,2м/с , удар не упругий какова скорость вагонов после взаимодействия ?

Ответы на вопрос

m1U1+m2U2=U' * (m1+m2) (в векторной форме, те у скорости наверху поставьте стрелочки)
m1U1+m2U2=U' * (m1+m2) (без стрелочек)
U'=m1U1+m2U2 / (m1+m2)
Тонны переведем в кг
Подставь значения и ответ готов



Calculation of the final velocity of the wagons after the collision
To calculate the final velocity of the wagons after the collision, we can use the principle of conservation of momentum. According to this principle, the total momentum before the collision is equal to the total momentum after the collision.
The momentum of an object is calculated by multiplying its mass by its velocity. Therefore, we can calculate the initial momentum of the first wagon (20 tons) and the second wagon (30 tons) before the collision, and then equate it to the final momentum of the combined wagons after the collision.
Let's denote the initial velocity of the first wagon as v1 (0.3 m/s) and the initial velocity of the second wagon as v2 (0.2 m/s). The masses of the wagons are given as 20 tons and 30 tons, respectively.
Using the principle of conservation of momentum, we can write the equation:
(mass of the first wagon * initial velocity of the first wagon) + (mass of the second wagon * initial velocity of the second wagon) = (total mass of the wagons * final velocity of the wagons)
Substituting the given values into the equation:
(20 tons * 0.3 m/s) + (30 tons * 0.2 m/s) = (50 tons * final velocity of the wagons)
Simplifying the equation:
(6 tons m/s) + (6 tons m/s) = (50 tons * final velocity of the wagons)
12 tons m/s = (50 tons * final velocity of the wagons)
To find the final velocity of the wagons, we can divide both sides of the equation by the total mass of the wagons (50 tons):
final velocity of the wagons = (12 tons m/s) / (50 tons)
Calculating the final velocity:
final velocity of the wagons = 0.24 m/s
Therefore, the final velocity of the wagons after the collision is 0.24 m/s.


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