Question

Аккумуляторная батарея имеет ЭДС 12 В И внутреннее сопротивление r = 0,1 Ом. Какое максимальное количество лампочек мощностью P = 25 Вт каждая, рассчитанных на напряжение U =10 В, можно подключить к источнику ЭДС, чтобы они горели нормальным накалом?

Answer 1

Чтобы лампы горели нормально, нам нужно напряжение в 10 В. исходя отсюда найдем максимальный допустимый ток для данного значения напряжения 

$U=E-Ir$

$I= \frac{E-U}{r} = \frac{12-10}{0,1} =20A$

найдем ток одной лампы по закону Ома $I^{'}= \frac{P}{U} = \frac{25}{10} =2,5A$

найдем количество лампочек $n= \frac{I}{I^{'}}= \frac{20}{2,5} =8$ штук

Ответ: 8 лампочек

Answer 2

Calculation of Maximum Number of Light Bulbs

To calculate the maximum number of light bulbs that can be connected to the power source, we need to consider the power rating of the light bulbs, the voltage of the power source, and the internal resistance of the battery.

Given: - Electromotive force (EMF) of the battery (E) = 12 V - Internal resistance of the battery (r) = 0.1 Ω - Power rating of each light bulb (P) = 25 W - Voltage for normal operation of the light bulbs (U) = 10 V

To calculate the maximum number of light bulbs, we can use the formula:

N = (E - U) / (P / U + r)

where: - N is the maximum number of light bulbs that can be connected - E is the electromotive force of the battery - U is the voltage for normal operation of the light bulbs - P is the power rating of each light bulb - r is the internal resistance of the battery

Substituting the given values into the formula:

N = (12 V - 10 V) / (25 W / 10 V + 0.1 Ω)

Simplifying the equation:

N = 2 V / (2.5 W/V + 0.1 Ω)

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