Question

Дано: а= 0,6м/с^2 t= 5c V= 23м/с Найти-S

Answer 1

Легко 14  = S
ltkbv 23 yf 5 

Answer 2

Problem Statement

We are given the following information: - Acceleration, a = 0.6 m/s^2 - Time, t = 5 s - Velocity, V = 23 m/s

We need to find the value of S.

Solution

To find the value of S, we can use the equations of motion. Let's go step by step.

1. We know that velocity is the derivative of displacement with respect to time. So, we can find the displacement function S(t) by integrating the acceleration function twice with respect to time.

S(t) = ∫(∫a(t) dt) dt

Let's find the expression for a(t) first. According to the given information, a = 0.6 m/s^2. Therefore, a(t) = 0.6.

Now, integrating a(t) with respect to t, we get:

∫a(t) dt = ∫0.6 dt = 0.6t + C1

Integrating again, we get:

S(t) = ∫(0.6t + C1) dt = 0.3t^2 + C1t + C2

Here, C1 and C2 are constants of integration.

2. Now, we can use the given information to find the values of C1 and C2.

We are given that V = 23 m/s. At t = 0, the initial velocity is 0. Therefore, we can substitute t = 0 and V = 0 in the equation for velocity to find C1.

V = 0.6t - 0.6(0) + C1

23 = 0.6(0) + C1

C1 = 23

Next, we can substitute t = 0 and S = 0 in the equation for displacement to find C2.

S = 0.3t^2 + C1t + C2

0 = 0.3(0)^2 + 23(0) + C2

C2 = 0

Therefore, the equation for displacement becomes:

S(t) = 0.3t^2 + 23t

3. Finally, we can substitute t = 5 in the equation for displacement to find the value of S.

S(5) = 0.3(5)^2 + 23(5)

S(5) = 7.5 + 115

S(5) = 122.5 m/s

Therefore, the value of S is 122.5 m.