Question

Тело брошенное с вышки в горизонтальном направлении со скоростью 20 м/с. Определите скорость и её направление в конце 2 секунды.

Answer 1

V=v0+gt
v=20м/с+ 10м/с*2с=40м/с

Answer 2

Problem Analysis

We are given that a body is thrown horizontally from a tower with a speed of 20 m/s. We need to determine the speed and direction of the body after 2 seconds.

Solution

To solve this problem, we can use the equations of motion for horizontal motion. Since the body is thrown horizontally, the initial vertical velocity is zero.

The equation for horizontal displacement is given by:

x = v0 * t

where: - x is the horizontal displacement - v0 is the initial horizontal velocity - t is the time

The equation for horizontal velocity is constant and given by:

v = v0

where: - v is the horizontal velocity - v0 is the initial horizontal velocity

Using these equations, we can find the horizontal displacement and velocity of the body after 2 seconds.

Calculation

Given: - Initial horizontal velocity (v0) = 20 m/s - Time (t) = 2 seconds

Using the equation for horizontal displacement, we can find the horizontal displacement (x):

x = v0 * t

Substituting the given values:

x = 20 * 2 = 40 meters

Therefore, the horizontal displacement of the body after 2 seconds is 40 meters.

Using the equation for horizontal velocity, we can find the horizontal velocity (v):

v = v0

Substituting the given value:

v = 20 m/s

Therefore, the horizontal velocity of the body after 2 seconds is 20 m/s.

Answer

The speed of the body after 2 seconds is 20 m/s in the horizontal direction. The body has traveled a horizontal distance of 40 meters after 2 seconds.

Please let me know if I can help you with anything else.