Question

100 кг водяного пара при 100 с пропускают через 1 т воды при 0 с. До какой температуры нагреется вода?

Answer 1

Дано :
m1=100кг 
t1 = 100 C 
m2= 1T=1000кг 
t2=0 C  
Найти: 
tб ( t баланса) 
C воды общее. 
С=4200Дж\кг*С 
r=2300000 Дж\кг 

Решение: 
Q1=rm1 
Q2=cm1(t1-tб) 
Q3=cm2(tб-t2) 
Q1+Q2=Q3 
rm1+cm1(t1-tб) = cm2(tб -t2) 
Подставим числа:
230000000+42000000-420000tб=4200000tб 
272000000=4620000tб 
tб=58.87 градусов. 
Ответ: 58.87градусов цельсия.

Answer 2

Heating Water with 100 kg of Steam

To determine the temperature to which water will be heated when 100 kg of steam at 100°C is passed through 1 ton (1000 kg) of water at 0°C, we can use the principle of heat transfer.

The heat transfer equation can be expressed as:

Q = m * c * ΔT

Where: - Q is the heat transferred - m is the mass of the substance - c is the specific heat capacity of the substance - ΔT is the change in temperature

In this case, we have 100 kg of steam at 100°C and 1 ton (1000 kg) of water at 0°C.

To find the temperature to which the water will be heated, we need to calculate the heat transferred from the steam to the water.

Calculation

First, let's calculate the heat transferred from the steam to the water.

The specific heat capacity of water is approximately 4.18 J/g°C.

Using the equation Q = m * c * ΔT, we can calculate the heat transferred:

Q = (100 kg) * (4.18 J/g°C) * (T - 0°C)

Where T is the final temperature of the water.

Since we have 1 ton (1000 kg) of water, we can convert the mass of water to kilograms:

Q = (1000 kg) * (4.18 J/g°C) * (T - 0°C)

Now, let's calculate the heat transferred from the steam to the water:

Q = (100 kg) * (2257 J/g°C) * (100°C - T)

Setting the two equations equal to each other, we can solve for T:

(1000 kg) * (4.18 J/g°C) * (T - 0°C) = (100 kg) * (2257 J/g°C) * (100°C - T)

Simplifying the equation:

(1000 kg) * (4.18 J/g°C) * T = (100 kg) * (2257 J/g°C) * (100°C - T)

Solving for T:

(1000 kg) * (4.18 J/g°C) * T = (100 kg) * (2257 J/g°C) * 100°C - (100 kg) * (2257 J/g°C) * T

(1000 kg) * (4.18 J/g°C