Question

В поле точечного заряда 10-7 Кл две точки расположены на расстоянии 0,15 и 0,2 м от заряда, Найдите разность потенциалов этих точек.

Answer 1

U = фи1-фи2

 

фи1=k*q/r1 = 9*10^9*10^-7/0.15=6000B

фи2=k*q/r2=9*10^9*10^-7/0.2=4500B

U= 6000-4500=1500B

 

 

 

Answer 2

Calculation of Potential Difference

To find the potential difference between two points in the electric field of a point charge, we can use the formula:

V = k * (q / r)

Where: - V is the potential difference between the two points, - k is the electrostatic constant (approximately equal to 9 x 10^9 Nm^2/C^2), - q is the charge of the point charge, - r is the distance between the point charge and the point where the potential difference is being calculated.

In this case, we have a point charge with a charge of 10^-7 C, and two points located at distances of 0.15 m and 0.2 m from the charge.

Let's calculate the potential difference between these two points.

Using the formula, we have:

V1 = k * (q / r1) V2 = k * (q / r2)

Substituting the given values:

V1 = (9 x 10^9 Nm^2/C^2) * (10^-7 C / 0.15 m) V2 = (9 x 10^9 Nm^2/C^2) * (10^-7 C / 0.2 m)

Now, let's calculate the values.

V1 = 6 x 10^2 V V2 = 4.5 x 10^2 V

Therefore, the potential difference between the two points is 600 V and 450 V, respectively.

Please note that the above calculations are based on the provided information and the formula for potential difference in an electric field.