Question

Шар упал с высоты 245 м.Какой путь он прошёл в последнюю секунду падения

Answer 1

Тело падало,значит двигалось равноускоренно.каждую секунду тело получала +10 м/с ускорения свободного падения g.10+20+30+40+50+60=210;245-210=35 метров

Answer 2

Calculating the Distance Fallen

To calculate the distance fallen in the last second of the fall, we can use the following kinematic equation:

\[ s = ut + (1/2)at^2 \]

Where: - s = distance fallen - u = initial velocity (which is 0 m/s as the object is falling from rest) - t = time (which is 1 second for the last second of the fall) - a = acceleration due to gravity (which is approximately 9.81 m/s^2)

Calculation

Using the above kinematic equation, we can calculate the distance fallen in the last second:

\[ s = (0 * 1) + (1/2) * 9.81 * 1^2 \]

\[ s = 0 + 4.905 \]

\[ s = 4.905 meters \]

Therefore, the object fell a distance of approximately 4.905 meters in the last second of its fall.