Question

Определите увеличение внутренней энергии одноатомного газа,находящегося под давлением 1,5*10^5 па, если его объем изобарно увеличивается на 0,6 м^3. Вычислите работу и количество теплоты получаемое при этом процессе

Answer 1

А=pV 
A=1.5*10^ 3Па*0.6 м^3=900 Дж
Q=A=900 Дж
дельта U=0 т.к это изобарный процесс

Answer 2

Calculation of the Increase in Internal Energy

To determine the increase in internal energy of a monoatomic gas, we need to consider the work done on the gas and the heat transferred to the gas during the process.

Given: - Pressure (P) = 1.5 * 10^5 Pa - Change in volume (ΔV) = 0.6 m^3

To calculate the increase in internal energy (ΔU), we can use the first law of thermodynamics, which states that the change in internal energy of a system is equal to the heat added to the system minus the work done by the system:

ΔU = Q - W

Calculation of Work (W)

In an isobaric process, the pressure remains constant. Therefore, the work done on the gas can be calculated using the formula:

W = P * ΔV

Substituting the given values:

W = (1.5 * 10^5 Pa) * (0.6 m^3)

Calculating the value of W will give us the work done on the gas.

Calculation of Heat (Q)

To calculate the heat transferred to the gas (Q), we need additional information such as the specific heat capacity at constant pressure (Cp) or the change in temperature (ΔT). Without this information, we cannot directly calculate the heat transferred.

Please provide the specific heat capacity at constant pressure (Cp) or the change in temperature (ΔT) for further calculations.