Question

Растянутая на 2 см стальная пружина обладает потенциальной энергией упругой деформации 4 Дж. При растяжении этой пружины еще на 2 см ее потенциальная энергия упругой деформации увеличится на сколько? НУЖНО РЕШЕНИЕ ЗАРАНЕЕ спасибо

Answer 1

Поскольку энергия пружины пропорциональна квадрату удлинения, при увеличении растяжения в 2 раза энергия увеличилась в 4 раза и составила
Е₂ = 4E₁ = 4·4 = 16 Дж
Следовательно, энергия увеличилась на
ΔE = E₂ - E₁ = 16 - 4 = 12 Дж

Answer 2

Calculation of the Increase in Potential Energy

To calculate the increase in potential energy of a steel spring when stretched by an additional 2 cm, we need to use the formula for the potential energy of elastic deformation:

Potential Energy of Elastic Deformation (U) = (1/2) * k * x^2

Where: - U is the potential energy of elastic deformation - k is the spring constant - x is the displacement or change in length of the spring

In this case, we are given that the initial potential energy of the spring is 4 J and the spring is stretched by an additional 2 cm.

Let's assume the initial displacement of the spring is x1 and the final displacement after stretching is x2. We can calculate the increase in potential energy (ΔU) using the following equation:

ΔU = (1/2) * k * (x2^2 - x1^2)

To find the increase in potential energy, we need to know the spring constant (k) and the initial displacement (x1) of the spring. Unfortunately, the given information does not include these values. Without these values, it is not possible to calculate the increase in potential energy.

If you have any additional information or if there is anything else I can assist you with, please let me know!