Question

Тормозной путь автомобиля,движущегося со скоростью 15 км/ч, равен 1,5м.Каким будет тормозной путь этого же автомобиля при скорости 90км/ч?Ускорение автомобиля при торможении в обоих случаях считайте одинаковым.Подробно пожалуйста, заранее спасибо.

Answer 1

90км/час будет приблезительно 27 м/с²

Answer 2

Calculating Braking Distance

To calculate the braking distance of a car, we can use the formula:

Braking distance = (Initial velocity^2) / (2 * acceleration)

Given that the initial velocity is 15 km/h and the braking distance is 1.5 m, we can calculate the acceleration using the above formula.

Using the provided information, we can calculate the acceleration as follows:

Initial velocity (u) = 15 km/h = 15 * (1000/3600) m/s = 4.17 m/s Braking distance (s) = 1.5 m

Now, we can calculate the acceleration (a) using the formula:

a = (v^2 - u^2) / (2 * s)

Where: - v = final velocity (which is 0 m/s as the car comes to a stop) - u = initial velocity - s = braking distance

Let's calculate the acceleration using the given values.

Calculating Acceleration

a = (0 - (4.17)^2) / (2 * 1.5) a = (-17.35) / 3 a ≈ -5.78 m/s^2

So, the acceleration of the car during braking is approximately -5.78 m/s^2.

Braking Distance at 90 km/h

Now, we need to calculate the braking distance at a speed of 90 km/h using the same acceleration.

Given: - Initial velocity (u) = 90 km/h = 90 * (1000/3600) m/s = 25 m/s - Acceleration (a) = -5.78 m/s^2

We can use the same formula to calculate the braking distance at 90 km/h:

Braking distance = (Initial velocity^2) / (2 * acceleration)

Let's calculate the braking distance at 90 km/h using the given acceleration.

Braking distance = (25^2) / (2 * (-5.78)) Braking distance ≈ 52.56 m

Therefore, the braking distance of the car at a speed of 90 km/h, assuming the same acceleration, is approximately 52.56 meters.

I hope this helps! If you have further questions, feel free to ask.