Question

За 40 сек поезд уменьшил свою скорость от 30м/с до 10 м/с. какой путь он прощел за это время и с каким ускорением двигался?

Answer 1

А=(V-Vo)/t
а=(10-30)/40= -0,5м/с2
S=Vot+at2/2
S=30*40+(-0,5*1600)/2=1200-400=800м

Answer 2

Calculation of Distance and Acceleration

To calculate the distance traveled by the train and the acceleration during the 40-second interval, we can use the following information:

- Initial velocity (u) = 30 m/s - Final velocity (v) = 10 m/s - Time (t) = 40 seconds

To calculate the distance (s) traveled by the train, we can use the formula:

s = (u + v) * t / 2 Substituting the given values:

s = (30 + 10) * 40 / 2 = 40 * 40 / 2 = 800 meters

Therefore, the train traveled a distance of 800 meters during the 40-second interval.

To calculate the acceleration (a) of the train, we can use the formula:

a = (v - u) / t Substituting the given values:

a = (10 - 30) / 40 = -20 / 40 = -0.5 m/s^2

Therefore, the train had an acceleration of -0.5 m/s^2 during the 40-second interval.

Conclusion

During the 40-second interval, the train traveled a distance of 800 meters and had an acceleration of -0.5 m/s^2.