Question

С крутого берега реки высотой 20 м. бросают камень в горизонтальном направлении со скоростью 15 м/с. Камень пролетает вдоль воды 30м. По этим данным вычислите ускорение свободного падения. (Решите пожалуйста с дано и решением)

Answer 1

H=20 м    v=15 м/с    s=30 м   g=?
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t=s/v=30/15=2 c
h=g*t²/2
g=2*h/t²=2*20/4=10 м/с²
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Answer 2

Given Information:

- Height of the cliff: 20 m - Initial horizontal velocity of the stone: 15 m/s - Distance traveled by the stone along the water: 30 m

Solution:

To find the acceleration due to gravity, we can use the following equation of motion:

h = ut + (1/2)gt^2

Where: - h is the height of the cliff (20 m) - u is the initial horizontal velocity of the stone (15 m/s) - g is the acceleration due to gravity (to be determined) - t is the time taken by the stone to reach the water surface

Since the stone is thrown horizontally, the time taken to reach the water surface can be calculated using the horizontal distance traveled and the initial horizontal velocity:

t = d/u

Where: - d is the horizontal distance traveled by the stone (30 m) - u is the initial horizontal velocity of the stone (15 m/s)

Substituting the values into the equation, we have:

20 = (15 * (30/15)) + (1/2)g * (30/15)^2

Simplifying the equation, we get:

20 = 30 + (1/2)g * 2

20 - 30 = g

g = -10 m/s^2

Therefore, the acceleration due to gravity is -10 m/s^2.

Note: The negative sign indicates that the acceleration due to gravity acts in the opposite direction to the initial velocity of the stone.