Question

Чему равны период и частотаколебаниягруза,колебающегося напружине ,если в начальныймомент скорость груза равнанулю и за 8 с он прошелчерез положениеравновесия 64 раза?Ответ должен быть 0,25с ;4Гц.Пожалуйста помогите.Нужно решение данной задачи.

Answer 1

Ты лучший с фоткой пожалуйста

Answer 2

Solving for Period and Frequency of Oscillation

To find the period and frequency of oscillation of a mass on a spring, we can use the given information about the number of oscillations and the time taken.

Given: - Initial velocity of the mass, \( v_0 = 0 \) - Number of oscillations, \( n = 64 \) - Time taken, \( t = 8 \, \text{s} \)

Calculating the Period

The period of oscillation can be calculated using the formula: \[ T = \frac{t}{n} \]

Substituting the given values: \[ T = \frac{8 \, \text{s}}{64} = 0.125 \, \text{s} \]

So, the period (T) of the oscillation is 0.125 seconds.

Calculating the Frequency

The frequency of oscillation can be calculated using the formula: \[ f = \frac{1}{T} \]

Substituting the value of the period: \[ f = \frac{1}{0.125 \, \text{s}} = 8 \, \text{Hz} \]

So, the frequency (f) of the oscillation is 8 Hz.

Therefore, the period of oscillation is 0.125 s and the frequency is 8 Hz.