Question

В лифте, движущимся вниз с ускорением 2 м/c, находится пассажир массой 50 кг. Чему равен модуль силы тяжести, действующей на пассажира?

Answer 1

Сила тяжести не зависит от движения лифта
Fт=mg,g=9,8м/с2
Fт=50*10=500Н

Answer 2

Calculating the Force of Gravity in an Elevator Moving Downward

To calculate the force of gravity acting on a passenger in an elevator moving downward with an acceleration of 2 m/s^2 and a passenger mass of 50 kg, we can use the formula:

Force of Gravity (Fg) = mass (m) x acceleration due to gravity (g)

Given: - Mass of the passenger (m) = 50 kg - Acceleration due to gravity (g) = 9.8 m/s^2 (standard value)

We can calculate the force of gravity using the given acceleration in the elevator.

Calculation

Using the formula Fg = m * g, where m = 50 kg and g = 9.8 m/s^2, we get: Fg = 50 kg * 9.8 m/s^2 = 490 N

Therefore, the module of the force of gravity acting on the passenger in the elevator is 490 N.