Question

Какова сила притяжения точечных зарядов q1=-3 мКл и q2=4 мКл, находящихся на расстоянии 12 м?

Answer 1

F = kq₁q₂ / r²
F = 9 * 10⁹ Н*м²/Кл² * 3 * 10⁻³ Кл * 4 * 10⁻³ Кл / 144 м² = 750 Н

Answer 2

Calculating the Force of Attraction between Point Charges

To calculate the force of attraction between point charges q1 = -3 mC and q2 = 4 mC, located at a distance of 12 m, we can use Coulomb's law, which states that the force between two point charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

Coulomb's Law states that the force (F) between two point charges q1 and q2 separated by a distance (r) is given by the formula: \[ F = \frac{k \cdot |q1 \cdot q2|}{r^2} \] Where: - F is the force between the charges, - k is the Coulomb's constant, approximately equal to 8.9875 x 10^9 N m^2/C^2, - q1 and q2 are the magnitudes of the charges, and - r is the distance between the charges.

Calculation

Using the given values: - q1 = -3 mC - q2 = 4 mC - r = 12 m

We can calculate the force of attraction using the formula: \[ F = \frac{k \cdot |q1 \cdot q2|}{r^2} \]

\[ F = \frac{8.9875 \times 10^9 \times |(-3 \times 10^{-3}) \times (4 \times 10^{-3})|}{12^2} \]

\[ F = \frac{8.9875 \times 10^9 \times 12 \times 10^{-6}}{144} \]

\[ F ≈ \frac{107.85 \times 10^3}{144} \]

\[ F ≈ 748.96 N \]

So, the force of attraction between the point charges q1 = -3 mC and q2 = 4 mC, located at a distance of 12 m, is approximately 748.96 N.