Question

Определи количество энергии, необходимую для испарения воды массой 625г, взятую при температуре 100°С испарить? L испарения=2,3*10^6дж/кг помогите!!!!!!!​ Хелп ми!!?!!!!!?!!!!?!?????!!??!??!!!!

Answer 1

Ответ:

1437,5кДж

Объяснение:

на фото подробное решение

Answer 2

Calculating the Energy Required to Vaporize Water

To calculate the energy required to vaporize water, we can use the formula:

Q = m * L

Where: - Q = energy required (in joules) - m = mass of water (in kilograms) - L = latent heat of vaporization (in joules per kilogram)

Given: - Mass of water, m = 625g = 0.625kg - Latent heat of vaporization, L = 2.3 * 10^6 J/kg

Calculation

Using the formula, we can calculate the energy required to vaporize the given mass of water:

Q = 0.625kg * (2.3 * 10^6 J/kg)

Q = 1.4375 * 10^6 J

So, the energy required to vaporize 625g of water at 100°C is approximately 1.4375 * 10^6 joules.