Question

коэффициент жесткости пружины 320 H/м на сколько сантиметров нужно сжать пружину чтобы в ней был запас энергии 50 мДж

Answer 1

Ответ:1,768 см

Дано:

E = 50 мДж = 0,05 Дж

k = 320 H/м

Найти:

ΔL  - ?

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Решение:

E = 0,5 k · ΔL²

ΔL =√(2E/k)

ΔL = √(2 · 0,05 : 320) = √0,0003125 м ≈ 0,01768 м = 1,768 см

Объяснение:

Answer 2

Calculating Compression of a Spring to Store Energy

To calculate the compression needed to store a certain amount of energy in a spring, we can use the formula for the potential energy stored in a spring:

$U = \frac{1}{2} k x^2$

Where: - $U$ = potential energy stored in the spring (in joules) - $k$ = spring constant (in newtons per meter, N/m) - $x$ = compression or extension of the spring from its equilibrium position (in meters)

Given: - Spring constant, $k = 320$ N/m - Desired potential energy, $U = 50$ mJ = $50 \times 10^{-3}$ J

We can rearrange the formula to solve for $x$:

$x = \sqrt{\frac{2U}{k}}$

Calculation

Substitute the given values into the formula: $x = \sqrt{\frac{2 \times 50 \times 10^{-3}}{320}}$

Calculating: $x ≈ \sqrt{\frac{0.1}{320}} ≈ \sqrt{0.0003125} ≈ 0.0177$ meters

So, to store 50 mJ of energy in a spring with a spring constant of 320 N/m, the spring needs to be compressed by approximately 0.0177 meters.