Question

Во время аварийного торможения на сухом асфальте автомобиль движется с ускорением в 8 м/с^2. Каков тормозной путь автомобиля при скорости 72км/ч

Answer 1

Ответ:

25 м

Объяснение:

a= -8 м/с²    vo=20 м/с     s=?

===

v=0

s=(v²-vo²)/(2*a)=(0-20²)/(2*(-8))=25 м

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Answer 2

Calculating Braking Distance

To calculate the braking distance of a car during emergency braking on dry asphalt, we can use the following formula:

Braking distance = (Initial velocity^2) / (2 * acceleration)

Given: Initial velocity = 72 km/h = 20 m/s (since 1 km/h = 1000 m/3600 s) Acceleration = -8 m/s^2 (negative because it's deceleration during braking)

Plugging these values into the formula: Braking distance = (20^2) / (2 * -8) = 400 / -16 = -25 m

The negative sign indicates that the car would not be able to stop within this distance, assuming constant deceleration. This result suggests that the car would not be able to stop in time under the given conditions.