Question

определить мощность электродвигателя приводящего в движение грузовой лифт, если его масса с грузом 800 кг, высота 10 м, время подъёма 2с, КПД 0,8

Answer 1

Ответ:

P = Q*n/t = 0,8mgh/t = 0,8 * 800 * 10 * 10Вт/2 = 32000Вт

Ответ: 32000Вт

Answer 2

Calculating the Power of the Electric Motor for the Freight Elevator

To calculate the power of the electric motor driving the freight elevator, we can use the formula:

Power (P) = Work done / Time

Where: - Work done = Force × Distance - Force = Mass × Acceleration due to gravity - Distance = Height lifted - Time = Time taken for the lift

Given: - Mass of the elevator and cargo (m) = 800 kg - Height lifted (h) = 10 m - Time taken for the lift (t) = 2 s - Efficiency (η) = 0.8

First, we can calculate the work done, which is the force required to lift the elevator and cargo to the given height.

Calculating Force and Work Done

The force required to lift the elevator and cargo can be calculated using the formula:

Force = Mass × Acceleration due to gravity

The acceleration due to gravity is approximately 9.8 m/s^2.

Force = 800 kg × 9.8 m/s^2

Now, we can calculate the work done using the formula:

Work done = Force × Distance

Work done = (800 kg × 9.8 m/s^2) × 10 m

Calculating Power

Now that we have the work done, we can calculate the power using the formula:

Power (P) = Work done / Time

Power (P) = (800 kg × 9.8 m/s^2 × 10 m) / 2 s

Accounting for Efficiency

Finally, we need to account for the efficiency of the system. The actual power required from the motor is higher than the calculated power due to losses, and it can be calculated by dividing the calculated power by the efficiency.

Actual Power = Power (P) / Efficiency

Actual Power = [(800 kg × 9.8 m/s^2 × 10 m) / 2 s] / 0.8

Result

The actual power of the electric motor required to drive the freight elevator is calculated to be approximately 3920 watts.